Question #325233

Tests made on the breaking strength of 10 pieces of a metal gave the following results: 578, 572, 570, 568, 572, 570, 570, 572, 598 and 584 kg. Test if the mean breaking strength of the wire can be assumed as 577 kg


1
Expert's answer
2022-04-11T10:58:57-0400

H0:μ=577H_0: \mu=577 kg

Ha:μ577H_a: \mu\neq577 kg


t=xμsnt=\frac{\overline{x}-\mu}{s\sqrt{n}}


x=xi/n=575.4\overline{x}=\sum{x_i}/n=575.4 kg


s=(xix)2n1=9.24s=\sqrt{\frac{\sum (x_i-\overline{x})|^2}{n-1}}=9.24 kg


t=575.45779.24/10=3.162t=\frac{575.4-577}{9.24/\sqrt{10}}=-3.162


df=n1=101=9df=n-1=10-1=9


critical value for α=0.05\alpha=0.05 :

tcrit=2.262t_{crit}=2.262


Since t>tcrit|t|>t_{crit} , we reject the null hypothesis.

The mean breaking strength of the wire cannot be assumed as 577 kg


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