A coin is tossed twice. Let Z denote the number of heads on
the first toss and W , the total number of heads on the two tosses. If
the coin is unbalanced and a head has a 60% chance of occurring,
find
(a) the joint distribution of W and Z .
(b) the marginal distribution of W .
(c )the marginal distribution of Z .
(d) the probability that at least 1 head occurs.
a:Z takes values 0,1W takes values 0,1,2P(Z=0,W=0)=0.4⋅0.4=0.16P(Z=0,W=1)=0.4⋅0.6=0.24P(Z=1,W=1)=0.6⋅0.4=0.24P(Z=1,W=2)=0.6⋅0.6=0.36b:P(W=0)=0.4⋅0.4=0.16P(W=1)=0.4⋅0.6+0.6⋅0.4=0.48P(W=2)=0.6⋅0.6=0.36c:P(Z=0)=0.4P(Z=1)=0.6d:P(W⩾1)=1−P(W=0)=1−0.16=0.84a:\\Z\,\,takes\,\,values\,\,0,1\\W\,\,takes\,\,values\,\,0,1,2\\P\left( Z=0,W=0 \right) =0.4\cdot 0.4=0.16\\P\left( Z=0,W=1 \right) =0.4\cdot 0.6=0.24\\P\left( Z=1,W=1 \right) =0.6\cdot 0.4=0.24\\P\left( Z=1,W=2 \right) =0.6\cdot 0.6=0.36\\b:\\P\left( W=0 \right) =0.4\cdot 0.4=0.16\\P\left( W=1 \right) =0.4\cdot 0.6+0.6\cdot 0.4=0.48\\P\left( W=2 \right) =0.6\cdot 0.6=0.36\\c:\\P\left( Z=0 \right) =0.4\\P\left( Z=1 \right) =0.6\\d:\\P\left( W\geqslant 1 \right) =1-P\left( W=0 \right) =1-0.16=0.84a:Ztakesvalues0,1Wtakesvalues0,1,2P(Z=0,W=0)=0.4⋅0.4=0.16P(Z=0,W=1)=0.4⋅0.6=0.24P(Z=1,W=1)=0.6⋅0.4=0.24P(Z=1,W=2)=0.6⋅0.6=0.36b:P(W=0)=0.4⋅0.4=0.16P(W=1)=0.4⋅0.6+0.6⋅0.4=0.48P(W=2)=0.6⋅0.6=0.36c:P(Z=0)=0.4P(Z=1)=0.6d:P(W⩾1)=1−P(W=0)=1−0.16=0.84
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