Answer to Question #319686 in Statistics and Probability for Tine

Question

consider a population consisting of 15,2,12,4,5,8,6,9 and 17.samples of size 5 are drawn from this popular

Answer 1

$C^5_9=\frac{9!}{5!4!}=126$ This is the number of combinations.

For example

(15,2,12,4,5)

(15,2,12,4,8)

(15,2,12,4,6)

(15,2,12,4,9)

(15,2,12,4,17)

(2,12,4,5,8)

(2,12,4,5,6)

(2,12,4,5,9)

(2,12,4,5,17)

(12,4,5,8,6)

(12,4,5,8,9)

(12,4,5,8,17)

(4,5,8,6,9)

(4,5,8,6,17)

(5,8,6,9,17)

(15,12,4,5,8)

(15,12,4,5,9)

(15,12,4,5,17)

(15,4,5,8,6)

(15,4,5,8,9)

(15,4,5,8,17)

(15,5,8,6,9)

(15,5,8,6,17)

(15,8,6,9,17)