The heights of the population of boys are normally distributed with a mean of 66 inches and al standard deviation of 8.9 inches. If a random sample of 40 boys is drawn from this population, what is the probability that the mean of this sample is greater than 64.5 inches?
"Z=\\frac{x-\\mu}{s\/\\sqrt{n}}=\\frac{64.5-66}{8.9\/\\sqrt{40}}=-1.07"
P(64.5<Z<66)=0.14231
P(Z>66)=0.5
P(Z>64.5)=0.5+0.14231=0.64231
Comments
Leave a comment