A sample size of 36 is to be selected from a population that has a mean of µ = 45 and standard deviation s of 10.
Mean of sampling distribution = 45
Standard error "=\\frac{\\sigma}{\\sqrt{n}}=\\frac{10}{\\sqrt{36}}=1.67"
Probability between 40 and 50
"P(40<x<50)=P(\\frac{40-45}{\\frac{10}{\\sqrt{36}}}<Z<\\frac{50-45}{\\frac{10}{\\sqrt{36}}})"
"=P(-3<Z<3)=P(Z<3)-P(Z<-3)"
"=0.9987-0.0013=0.9974"
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