Three airlines serve a Srinagar. Airline 'Amira' has 50% of all the scheduled flights, airline 'Biyas' has30% and airline 'chinar' has the remaining 20%. Their on-time rates are 80%, 65%, and 40%, respectively.
Part 2) A plane has just left on time. What is the probability that it was airline 'Amira'.
H1−Amira,H2−Biyas,H3−ChinarA−on timeP(H1)=0.5,P(H2)=0.3,P(H3)=0.2P(A∣H1)=0.8,P(A∣H2)=0.65,P(A∣H3)=0.4P(H1∣A)=P(A∣H1)P(H1)P(A∣H1)P(H1)+P(A∣H2)P(H2)+P(A∣H3)P(H3)==0.8⋅0.50.8⋅0.5+0.65⋅0.3+0.4⋅0.2=0.592593H_1-Amira,H_2-Biyas,H_3-Chinar\\A-on\,\,time\\P\left( H_1 \right) =0.5,P\left( H_2 \right) =0.3,P\left( H_3 \right) =0.2\\P\left( A|H_1 \right) =0.8,P\left( A|H_2 \right) =0.65,P\left( A|H_3 \right) =0.4\\P\left( H_1|A \right) =\frac{P\left( A|H_1 \right) P\left( H_1 \right)}{P\left( A|H_1 \right) P\left( H_1 \right) +P\left( A|H_2 \right) P\left( H_2 \right) +P\left( A|H_3 \right) P\left( H_3 \right)}=\\=\frac{0.8\cdot 0.5}{0.8\cdot 0.5+0.65\cdot 0.3+0.4\cdot 0.2}=0.592593H1−Amira,H2−Biyas,H3−ChinarA−ontimeP(H1)=0.5,P(H2)=0.3,P(H3)=0.2P(A∣H1)=0.8,P(A∣H2)=0.65,P(A∣H3)=0.4P(H1∣A)=P(A∣H1)P(H1)+P(A∣H2)P(H2)+P(A∣H3)P(H3)P(A∣H1)P(H1)==0.8⋅0.5+0.65⋅0.3+0.4⋅0.20.8⋅0.5=0.592593
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