4. The mean hemoglobin level in the blood for a certain large group of individuals is 21.0 grams per milliliter (g/ml). The standard deviation is 2 g/ml. If a sample of 25 individuals is selected, find the probability that the mean will be greater than 21.3 g/ml. Assume that the variable is normally distributed.
We have a normal distribution, "\\mu=21.0, \\sigma=2, n=25."
Let's convert it to the standard normal distribution,
"z=\\cfrac{\\bar{x}-\\mu}{\\sigma\/\\sqrt{n}}" =
"=\\cfrac{21.3-21.0}{2\/\\sqrt{25}}=0.75,"
"P(\\bar{X}>21.3)=1-P(\\bar{X}<21.3)=\\\\\n=1-P(Z<0.75)="
"=1-0.7734=0.2266" (from z-table)
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