Answer to Question #314518 in Statistics and Probability for Tobi

Question

The class gained a mean of μ = 24 and a standard deviation of a = 8.48 and X= 6

a. What percentage of scores are lower than your score? Show Steps 1 to 4 completely.

Answer 1

$\mu =24~~\sigma=8.48~~X=6$

$Z=\dfrac{X-\mu}{\sigma}=\dfrac{6-24}{8.48}$

$Z=-2.12$

From normal distribution tables

$P=0.017$

Percentage $=1.7\%$