A random sample of 900 members is found to have a mean of 4.45 CM can it be reasonably regarded as a sample from a large population whose mean is 5 cm and variance is 4 cm square obtain the 95% confidence limit for the mean in the population
"95\\%CI=(\\bar x-t_{0.025,n-1}\\frac{\\sigma}{\\sqrt{n}}, \\bar x+t_{0.025,n-1}\\frac{\\sigma}{\\sqrt{n}})="
"=(4.45-1.963\\frac{2}{\\sqrt{900}}, 4.45+1.963\\frac{2}{\\sqrt{900}})="
"=(4.319, 4.581)."
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