Given the population 3 5 8 9 and 10. Suppose samples of size 3 are drawn from this population
Population size N=5N=5N=5
Sample size n=3n=3n=3
mean
μ=∑i=1i=NXiN\mu=\dfrac{\sum_{i=1}^{i=N} X_i}{N}μ=N∑i=1i=NXi
μ=3+5+8+9+105\mu =\dfrac{3+5+8+9+10}{5}μ=53+5+8+9+10
μ=7.0\mu=7.0μ=7.0
Standard deviation
σ=∑(X−Xˉ)2n\sigma=\sqrt {\dfrac {\sum (X-\bar X)^2}n}σ=n∑(X−Xˉ)2
σ=(3−7)2+(5−7)2+(8−7)2+(9−7)2+(10−7)25\sigma=\sqrt \frac{{(3-7)^2+(5-7)^2+(8-7)^2+(9-7)^2+(10-7)^2}}5σ=5(3−7)2+(5−7)2+(8−7)2+(9−7)2+(10−7)2
σ=16+4+1+4+95\sigma=\sqrt {\dfrac{16+4+1+4+9}5}σ=516+4+1+4+9
σ=2.61\sigma=2.61σ=2.61
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