We have a normal distribution, μ=18.5,σ=2.5.
Let's convert it to the standard normal distribution, z=σx−μ.
(a) z=2.520−18.5=0.6;
P(X>20)=P(Z>0.6)=1−P(Z<0.6)=
=1−0.7257=0.2743 (from z-table).
(b) z1=2.516−18.5=−1,z2=2.518−18.5=−0.2,
P(16<X<18)=P(−1<Z<−0.2)=P(Z<−0.2)−P(Z<−1)=
=0.4207−0.1587=0.2620 (from z-table).
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