What is the probability that a market inspector will discover, at most five, but greater than two violations of the public health code?
*The question is incomplete and the probability table shown below.
(a) The probability that a market inspector will discover, at most five, but greater than two violations
P(5or4or3)=P(5)+P(4)+P(3)P(5 or 4or 3)= P(5)+P(4)+P(3)P(5or4or3)=P(5)+P(4)+P(3)
=0.02+0.05+0.13=0.02+0.05+0.13=0.02+0.05+0.13
=0.2=0.2=0.2
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