An electronic company in Laguna manufactures resistors that have a mean resistance of 120 ohms and a standard deviation of 13 ohms. Find the probability that a random sample of 40 resistors will have an average resistance greater than 114 ohms.
The following are the population mean (μ)=120, population standard deviation (σ) =13 and sample size (n)=40
The corresponding z-value needed to be computed is:
"Z= \\frac{x-\\mu}{\\frac{\\sigma}{\\sqrt{n}}}"
="\\frac{114-120}{\\frac{13}{\\sqrt{40}}}"
=-2.92
"Pr( \nX\n\n \u2265114)=P(Z\\geq-2.92)"
=1-"P(Z\\leq-2.92)"
=1-0.0018
=0.9982
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