Suppose that contamination particle size (in micrometers) can be modeled as f(x) =
2x^−3
for x > 1. Determine the mean and standard deviation of X.
Mean: E(X)=∫−∞+∞xf(x)dx=2∫1+∞x−2dx=−2x∣1+∞=2E(X)=\int_{-\infty}^{+\infty}xf(x)dx=2\int_{1}^{+\infty}x^{-2}dx=-{\frac 2 x}|_1^{+\infty}=2E(X)=∫−∞+∞xf(x)dx=2∫1+∞x−2dx=−x2∣1+∞=2
Variance: V(X)=E(X2)−E2(X)=∫−∞+∞x2f(x)dx−4=2∫1+∞x−1dx−4=2ln(x)∣1+∞−4=+∞−4=+∞V(X)=E(X^2)-E^2(X)=\int_{-\infty}^{+\infty}x^2f(x)dx-4=2\int_{1}^{+\infty}x^{-1}dx-4=2ln(x)|_1^{+\infty}-4=+\infty-4=+\inftyV(X)=E(X2)−E2(X)=∫−∞+∞x2f(x)dx−4=2∫1+∞x−1dx−4=2ln(x)∣1+∞−4=+∞−4=+∞
Standard deviation: σ(X)=V(X)=+∞\sigma(X)=\sqrt{V(X)}=+\inftyσ(X)=V(X)=+∞
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