Question #309887

Two fair cubical dice are thrown: one is red and one is blue. The random variable

M represents the score on the red die minus the score on the blue die.

a. Find the distribution of M.

b. Write down E(M).

c. Find Var (M)


Expert's answer

a) M={-5,-4,-3,-2,-1,0,1,2,3,4,5}

P(M=5)=P(M=5)=136P(M=-5)=P(M=5)={\frac 1 {36}}

P(M=4)=P(M=4)=236=118P(M=-4)=P(M=4)={\frac 2 {36}}={\frac 1 {18}}

P(M=3)=P(M=3)=336=112P(M=-3)=P(M=3)={\frac 3 {36}}={\frac 1 {12}}

P(M=2)=P(M=2)=436=19P(M=-2)=P(M=2)={\frac 4 {36}}={\frac 1 9}

P(M=1)=P(M=1)=536P(M=-1)=P(M=1)={\frac 5 {36}}

P(M=0)=636=16P(M=0)={\frac 6 {36}}={\frac 1 6}

b) Since the distribution is symmetrical about M=0, then mean of this distribution E(M)=0E(M)=0

c) Var(X)=E(X2)E2(X)=E(X2)=252136+242236+232336+222436+212536+202636=11036=5518Var(X)=E(X^2)-E^2(X)=E(X^2)=2*5^2*{\frac 1 {36}}+2*4^2*{\frac 2 {36}}+2*3^2*{\frac 3 {36}}+2*2^2*{\frac 4 {36}}+2*1^2*{\frac 5 {36}}+2*0^2*{\frac 6 {36}}={\frac {110} {36}}={\frac {55} {18}}


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