Laverny tosses an unbiased coin. He receives P100 if a head appears and he pays P40 it a tail appears Find the expected value and the variance of his gain.
Let X= the amount of money which Laverny receives.
x100−40p(x)0.50.5\begin{matrix} x & 100 & -40 \\ p(x) & 0.5 & 0.5 \end{matrix}xp(x)1000.5−400.5
(a) Expected value =E[X]=E[X]=E[X]
=0.5(100)+0.5(−40)=30=0.5(100)+0.5(-40)=30=0.5(100)+0.5(−40)=30
(b) Variance
E[X2]=0.5(100)2+0.5(−40)2=5800E[X^2]=0.5(100)^2+0.5(-40)^2=5800E[X2]=0.5(100)2+0.5(−40)2=5800
V(X)=E[X2]−(E[X])2=V(X)=V(X)=E[X^2]-(E[X])^2=V(X)=V(X)=E[X2]−(E[X])2=V(X)=
=5800−(30)2=4900=5800-(30)^2=4900=5800−(30)2=4900
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