Question #309114

The probabilities of a machine manufacturing 0, 1, 2, 3, 4, or 5 defective parts in one day are 0.75, 0.17, 0.04, 0.025, 0.01, and 0.005, respectively. Find the mean of the probability distribution.

Expert's answer

μ=00.75+10.17+20.04+30.025+40.01+50.005=0.39.\mu=0*0.75+1*0.17+2*0.04+3*0.025+4*0.01+5*0.005=0.39.


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