Question #307317

the weight of all male senior high school students from one province is measured and is found to be approximately normally distributed with a mean of 115 lbs and standard deviation of 3 lbs. find the percentile rank of the following weights?



A. 112 lbs



B. 115 lbs

1
Expert's answer
2022-03-08T07:11:02-0500

Population Mean (μ)=115(μ) =115

Population Standard Deviation (σ)=3(σ) =3


Z=XμσZ=\dfrac{X-μ}{σ}


(a)Z=1121153Z=\dfrac{112-115}{3}

Z=1.0Z=-1.0

From the standard normal distribution tables

Z(1.0)=0.15866Z(-1.0)=0.15866

=15.866th percentile


(b) Z=1151153Z=\dfrac{115-115}{3}

Z=0Z=0

From the standard normal distribution tables

Z(0)=0.50000Z(0)=0.50000

=50th percentile


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