1. A random sample of n = 100 measurements is obtained from a population with 𝜇 = 55 and 𝜎 = 20. Describe the sampling distribution for the sample means by computing the 𝜇𝑥̅ and 𝜎𝑥̅.
Since the sample size n=100 is statistically considered to be large (n>30), we assume that the mean of the sampling distribution of x̄ is equal to the population mean, μ.
Therefore;
𝜇𝑥̅ = μ = 55
Also, we estimate the sample standard deviation (𝜎𝑥̅.) using the formula:
𝜎𝑥̅. = "\\frac{\\sigma}{\\sqrt{n}}"
where "\\sigma" = population standard deviation
Given n=100 and "\\sigma" = 20
Then;
𝜎𝑥̅ = "\\frac{\\sigma}{\\sqrt{n}}" = "\\frac{20}{\\sqrt{100}}" = 2
Answer: The sampling distribution of the sample means has 𝜇𝑥̅ = 55 and 𝜎𝑥̅ =2
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