A deck of 52 playing cards has 4 aces. The probability of getting one ace less than zero
The number of aces in a pack of 52 card is 4, so the probability that the card drawn is an ace is,
P=4/52
Now, since one card is been chosen, then the total number of aces left is 3 and the total number of cards left is 52−1=51.
The probability that the card drawn is an ace is,
P=3/51
As two cards are been chosen, then the total number of aces left is 2 and the total number of cards left is 51−1=50.
The probability that the card drawn is an ace is,
P=2/50
Again, since three cards are been chosen, then the total number of aces left is 1 and the total number of cards left is 50−1=49.
The probability that the card drawn is an ace is,
P=1/49
By multiplication law of probability, we have
p= ( (4/52) * (3/51) * (2/50) * (1/49) )
Therefore the required probability equals 1/270725
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