Let X = X= X = mass of the soap: X ∼ N ( μ , σ 2 ) . X\sim N(\mu, \sigma^2). X ∼ N ( μ , σ 2 ) .
Given μ = 300 g , σ = 52 g . \mu=300\ g, \sigma=\sqrt{52}\ g. μ = 300 g , σ = 52 g .
a)
P ( X > 320 ) = 1 − P ( Z ≤ 320 − 300 52 ) P(X>320)=1-P(Z\le\dfrac{320-300}{\sqrt{52}}) P ( X > 320 ) = 1 − P ( Z ≤ 52 320 − 300 )
≈ 1 − P ( Z ≤ 2.7735 ) ≈ 0.002773 \approx1-P(Z\le2.7735)\approx0.002773 ≈ 1 − P ( Z ≤ 2.7735 ) ≈ 0.002773
b)
P ( 280 < X < 500 ) = P ( Z < 500 − 300 52 ) P(280<X<500)=P(Z<\dfrac{500-300}{\sqrt{52}}) P ( 280 < X < 500 ) = P ( Z < 52 500 − 300 )
− P ( Z ≤ 280 − 300 52 ) ≈ P ( Z ≤ 27.7350 ) -P(Z\le\dfrac{280-300}{\sqrt{52}})\approx P(Z\le27.7350) − P ( Z ≤ 52 280 − 300 ) ≈ P ( Z ≤ 27.7350 )
− P ( Z ≤ − 2.7735 ) ≈ 1 − 0.002773 -P(Z\le-2.7735)\approx1-0.002773 − P ( Z ≤ − 2.7735 ) ≈ 1 − 0.002773
≈ 0.997227 \approx0.997227 ≈ 0.997227
0.997227 ( 100 ) = 100 0.997227(100)=100 0.997227 ( 100 ) = 100 100 soaps will have masses between 280g and 500g.
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