Question #303793

1.It is claimed that the average weight of babies at birth is 3.4 kg. The average weight of a random sample of 30 newly born babies was determined.It was found out that the average weight was 3.1 kg. Is there a reason to believe that the average weight of babies at birth is not 3.4 kg? Assume that the population standard deviation is 1.1kg. Use 0.05 level of significance.



1
Expert's answer
2022-03-01T04:38:40-0500

The following null and alternative hypotheses need to be tested:

H0:μ=3.4H_0:\mu=3.4

H1:μ3.4H_1:\mu\not=3.4

This corresponds to a two-tailed test, for which a t-test for one mean, with unknown population standard deviation, using the sample standard deviation, will be used.

Based on the information provided, the significance level is α=0.05,\alpha = 0.05, df=n1=29df=n-1=29 degrees of freedom, and the critical value for a two-tailed test is tc=2.04523.t_c = 2.04523.

The rejection region for this two-tailed test is R={t:t>2.04523}.R = \{t: |t| > 2.04523\}.

The t-statistic is computed as follows:


t=Xˉμs/n=3.13.41.1/30=1.49379t=\dfrac{\bar{X}-\mu}{s/\sqrt{n}}=\dfrac{3.1-3.4}{1.1/\sqrt{30}}=-1.49379

Since it is observed that t=1.493792.04523=tc,|t| = 1.49379\le 2.04523=t_c, it is then concluded that the null hypothesis is not rejected.

Using the P-value approach:

The p-value for two-tailed, df=29df=29 degrees of freedom, t=1.49379,t=-1.49379, is p=0.146032,p=0.146032, and since p=0.146032>0.05=α,p=0.146032>0.05=\alpha, it is concluded that the null hypothesis is not rejected.

Therefore, there is not enough evidence to claim that the population mean μ\mu is different than 3.4,3.4, at the α=0.05\alpha = 0.05 significance level.



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