In a Math test, the mean score is 45 and the standard deviation is 4. Assuming normality, what is the probability that a score picked at random will lie below 45
Since "\\mu" =45 and "\\sigma"=4 we have:
P(X<45) = P(X-"\\mu" < 45-45) = P("\\frac{x-\\mu}\\sigma" < "\\frac{45-45}{4}")
Since
Z = "\\frac{x-\\mu}{\\sigma}" = "\\frac{45-45}{4}" = 0
Then
P(X<45) = P(Z<0)
From the normal distribution table, we find that:
P(Z<0) = 0.5
Therefore, we conclude that the probability that a score picked at random will lie below 45 is 0.5
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