fifty android tablet will be Delivered to a certain school for testing but five of them are defective.The principal will get two of these tablets for testing.Let X represent the defective tablet,Y for non defective tablet and Z represents the random variable for which a non defective tablet will occur.find the variables of Z
"P(Z=0)=\\frac{C_{45}^2C_5^0}{C_{50}^2}=\\frac{198}{245}."
"P(Z=1)=\\frac{C_{45}^1C_5^1}{C_{45}^2}=\\frac{45}{245}."
"P(Z=2)=\\frac{C_{45}^0C_5^2}{C_{50}^2}=\\frac{2}{245}."
Comments
Leave a comment