Question #302495


A fair spinner has 9 equal sections: 2 red, 3 blue and 4 green.

It is spun twice.

What is the probability of getting not green then green?


Expert's answer

P(GCG)=2+39(49)=2081P(G^CG)=\dfrac{2+3}{9}(\dfrac{4}{9})=\dfrac{20}{81}


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