Answer to Question #298165 in Statistics and Probability for ali

Question

An investigator thinks that people under the age of forty have vocabularies that are different than those of

people over sixty years of age. The investigator administers a vocabulary test to a group of 31 younger

subjects and to a group of 31 older subjects. Higher scores reflect better performance. The mean score for

younger subjects was 14.0 and the standard deviation of younger subject's scores was 5.0. The mean score

for older subjects was 20.0 and the standard deviation of older subject's scores was 6.0. Does this

experiment provide evidence for the investigator's theory?

Answer 1

Group 1 (Younger subjects)

$n_1=31\\\bar x_1=14\\s_1=5$

Group 2(Older subjects)

$n_2=31\\\bar x_2=20\\s_2=6$

To perform this test, we first check whether population variances for the two groups are equal.

We test,

$H_0:\sigma_1^2=\sigma_2^2\\vs\\H_1:\sigma_1^2\not=\sigma^2_2$

The test statistic is,

$F_c={s^2_2\over s_1^2}={36\over25}=1.44$

The critical value is,

$F_{{\alpha\over2},n_2-1,n_1-1}=F_{0.025,30,30}= 2.073944$

The null hypothesis is rejected if, $F_c\gt F_{0.025,30,30}$

Since $F_c=1.44\lt F_{0.025,30,30}=2.073944$, we fail to reject the null hypothesis and conclude that the population variances are equal.

We now perform hypothesis test on difference in means.

$H_0:\mu_1=\mu_2\\vs\\H_1:\mu_1\not=\mu_2$

The test statistic is,

$t_c={(\bar x_1-\bar x_2)\over \sqrt{sp^2({1\over n_1}+{1\over n_2})}}$

where $sp^2$ is the pooled sample variance given as,

$sp^2={(n_1-1)s_1^2+(n_2-1)s_2^2\over n_1+n_2-2}={(30\times25)+(30\times36)\over60}={1830\over60}=30.5$

Therefore,

$t_c={(14-20)\over \sqrt{30.5({1\over 31}+{1\over 31})}}={-6\over1.4028}=-4.28$

$t_c$ is compared with the table value at $\alpha=0.05$ with $n_1+n_2-2=31+31-2=60$ degrees of freedom.

The table value is,

$t_{{0.05\over2},60}=t_{0.025,60}= 2.000298$

The null hypothesis is rejected if $|t_c|\gt t_{0.025,60}.$

Now, $|t_c|=4.28\gt t_{0.025,60}=2.000298$ therefore, we reject the null hypothesis and conclude that there is enough evidence to support the researcher's claim that people under the age of forty have vocabularies that are different than those of people over sixty years of age at 5% significance level.