a certified public accountant (cpa) randomly selects 4 accounts for a group of 12 careful examination. The company being audited knows that 7 of the accounts contain - errors. what is the probability that all 3 accounts selected are error-free
Assume total no. of accounts the company has 14. (It is missing in question).
Total no. of selected accounts = 3
No. of accounts contain - errors = 7
No. of accounts errors free = 14 - 7 = 7
Required probability "=\\dfrac{^7C_3}{^{14}C_3}=\\dfrac{35}{364}=\\dfrac{5}{52}"
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