Answer to Question #295207 in Statistics and Probability for love

Question #295207

A shipment of 25 similar laptop computers to a retail outlet contains 5 that are defective. If a school makes a random purchase of 3 of these computers, find the probability when the school accidentally purchased 1 defective and 2 are nondefective computers? Convert your answer in decimals with three (3) significant figures.


1
Expert's answer
2022-02-09T13:45:56-0500

Let DD be the event that a laptop is defective. DD' is the event that a laptop is not defective.

The probability that a laptop is defective is, p(D)=525p(D)={5\over25} and p(D)=1p(D)=1525=2025p(D')=1-p(D)=1-{5\over25}={20\over25}

The probability that a school purchases 1 defective and 2 non-defective laptops is,

(525×2024×1923)+(2025×524×1923)+(2025×1924×523)=0.413({5\over25}\times{20\over24}\times{19\over23})+({20\over25}\times{5\over24}\times{19\over23})+({20\over25}\times{19\over24}\times{5\over23})=0.413


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