The probability that aa new automobile has a backup camera is 0.6. The probability
that a new automobile has a GPS system is 0.4. The probability that a new
automobile has both a backup camera and GPS is 0.2. If a new automobile is
selected at random, what is the probability that it has neither a backup camera nor a
GPS?
Let "A" be the event that the new automobile has a backup camera. Its probability is "p(A)=0.6"
Let "B" be the event that the new automobile has a GPS. Its probability is "p(B)=0.4".
The probability that the new automobile has both a backup camera and GPS is "p(A\\cap B)=0.2"
We first need to determine "p(A\\cup B)=p(A)+p(B)-p(A\\cap B)=0.6+0.4-0.2=0.8"
The probability that the new automobile has neither a backup camera nor a GPS is "1-0.8=0.2"
The required probability is 0.2
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