Question #287898

The pharmacy received 1000 bottles of mineral water. The probability that the bottle




will be broken during transportation is 0.003. Determine the likelihood that the pharmacy will




receive broken bottles: a) Two b) Less than two c) More than two d) At least one

Expert's answer

The normal approximation to the binomial distribution:

μ=np=10000.003=3.\mu=np=1000*0.003=3.

σ=np(1p)=10000.003(10.003)=1.73.\sigma=\sqrt{np(1-p)}=\sqrt{1000*0.003*(1-0.003)}=1.73.


a) P(1.5<X<2.5)=P(1.531.73<Z<2.531.73)=P(0.87<Z<0.29)=P(1.5<X<2.5)=P(\frac{1.5-3}{1.73}<Z<\frac{2.5-3}{1.73})=P(-0.87<Z<-0.29)=

=P(Z<0.29)P(Z<0.87)=P(Z<0.87)P(Z<0.29)=0.1937.=P(Z<-0.29)-P(Z<-0.87)=P(Z<0.87)-P(Z<0.29)=0.1937.


b) P(X<1.5)=P(Z<1.531.73)=P(Z<0.29)=0.3859.P(X<1.5)=P(Z<\frac{1.5-3}{1.73})=P(Z<-0.29)=0.3859.


c) P(X>2.5)=P(Z>2.531.73)=P(Z>0.87)=0.8078.P(X>2.5)=P(Z>\frac{2.5-3}{1.73})=P(Z>-0.87)=0.8078.


d) P(X>0.5)=P(Z>0.531.73)=P(Z>1.45)=0.9265.P(X>0.5)=P(Z>\frac{0.5-3}{1.73})=P(Z>-1.45)=0.9265.


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