The normal approximation to the binomial distribution:
μ=np=1000∗0.003=3.
σ=np(1−p)=1000∗0.003∗(1−0.003)=1.73.
a) P(1.5<X<2.5)=P(1.731.5−3<Z<1.732.5−3)=P(−0.87<Z<−0.29)=
=P(Z<−0.29)−P(Z<−0.87)=P(Z<0.87)−P(Z<0.29)=0.1937.
b) P(X<1.5)=P(Z<1.731.5−3)=P(Z<−0.29)=0.3859.
c) P(X>2.5)=P(Z>1.732.5−3)=P(Z>−0.87)=0.8078.
d) P(X>0.5)=P(Z>1.730.5−3)=P(Z>−1.45)=0.9265.
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