When a substance is synthesized under laboratory conditions, the probability of an
explosion in a separate experiment is p = 0.02. Determine the probability that in a series of 10
syntheses: 1) the explosion will occur three times; 2) the explosion will not occur
"n=10 \\\\\n\np = 0.02 \\\\\n\nq = 1 -0.02 = 0.98 \\\\\n\nP(X=x)=C(n,x)p^x q^{n-x}"
1) the explosion will occur three times
"P(X=3) = \\frac{10!}{3!(10-3)!} \\times 0.02^3 \\times 0.98^{10-3} = 0.000833"
2) the explosion will not occur
"P(X=0) = \\frac{10!}{0!(10-0)!} \\times 0.02^0 \\times 0.98^{10-0} = 0.817072"
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