Question #282382

n All maximum possible random samples of size 4 are drawn from the finite population comprising of X=2,4 a) Verify central limit theorem (CLT) in this random experiment b) Between what two sample means would you expect the middle 75% of sample means to fall c) Estimate population mean at 90% C


1
Expert's answer
2021-12-27T16:28:04-0500

a)

The central limit theorem (CLT) states that the distribution of sample means approximates a normal distribution as the sample size gets larger, regardless of the population's distribution.


sample mean

2,2,2,2 2

2,2,2,4 2.5

2,2,4,4 3

2,4,4,4 3.5

4,4,4,4 4


mean of the sample means:

μx=2+2.5+3+3.5+45=3\mu_{\overline{x}}=\frac{2+2.5+3+3.5+4}{5}=3

standard deviation of the sample means:

σx=(23)2+(2.53)2+(3.53)2+(43)25=1/2\sigma_{\overline{x}}=\sqrt{\frac{(2-3)^2+(2.5-3)^2+(3.5-3)^2+(4-3)^2}{5}}=1/\sqrt 2


mean of population:

μ=(2+4)/2=3\mu=(2+4)/2=3

standard deviation of population:

σ=(23)2+(43)22=1\sigma=\sqrt{\frac{(2-3)^2+(4-3)^2}{2}}=1


so,

μx=μ=3\mu_{\overline{x}}=\mu=3

σx=σ/n=1/4=1/2\sigma_{\overline{x}}=\sigma/\sqrt n=1/\sqrt 4=1/2


b)

At least 75% of the data will be within two standard deviations of the mean (Chebychev’s rule)

then:

μ±2σx=3±21/2=(2,4)\mu\pm 2\sigma_{\overline{x}}=3\pm 2\cdot1/ 2=(2,4)

the middle 75% of sample means falls between 2 and 4


c)

for 90% confidence interval of population mean:


z=±1.645=xμσ=x31z=\pm 1.645=\frac{x-\mu}{\sigma}=\frac{x-3}{1}


1.355<x<4.6451.355<x<4.645


sample means:



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