possible variants:
(1,1),(1,2),(2,1),(2,2),(1,3),(1,4),(3,1),(4,1),(2,3),(3,2),(3,3),
(2,4),(4,2),(3,4),(4,3),(4,4)
number of possible variants:
n=16
total number of variants:
N=36
probability that both number of dices are less than five:
P=n/N=16/36=4/9
Comments