Four coins are tossed. Let z be the random variable representing the number of heads that occur. What is the probability of the least number of times that heads may occur?
For the head to be displayed a tail is not displayed ,
In a case where 4 tails are displayed we then have 0 head
Z=0
When there are 3 tails displayed we have 1 head then it means
Z= 1
In a case where there is 2 tails displayed it also means there is 2 heads displayed hence
Z=2
And in a case where there is only 1 tail displayed the remaining 3 are heads hence
Z=3
And in a case where there is no tail displayed then there are 4 heads displayed meaning
Z= 4.
Hence the Z takes the values {0,1,2,3,4} .
The least number of times that heads may occur is zero with a probability of 1/16.
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