Answer to Question #277185 in Statistics and Probability for Kakaibabe

Question

Scores on a scholarship aptitude exam are normally distributed with a mean of 72 and a standard deviation of 8. What is the highest score that will place an applicant at the bottom 25% of the distribution?

Answer 1

Mean =72

Std dev = 8

To get 25% implies solving Q1.

P(X<x)=0.25

Using Excel the code is

NORMINV(0.25,72,8)

=66.60408