Question #276944

A water heater is designed to last an average of 16 years,the lifetime of such a heater can be modelled by an exponential random variables X with lambda value of 0.0625, suppose a heater is selected at random ,,,

What is the probability the heater will last at least 5 years


Suppose the heater last for 5 years what is the probability it will last for the other 5 years


1
Expert's answer
2021-12-08T11:15:14-0500

Let X=X= the lifetime of a heater: XExp(λ).X\sim Exp(\lambda).

Given λ=1/16=0.0625\lambda=1/16=0.0625

i.


P(X5)=eλ(5)=e0.0625(5)0.731616P(X\geq 5)=e^{-\lambda(5)}=e^{-0.0625(5)}\approx0.731616

ii.

The memoryless property says that


P(X>r+tX>r)=P(X>t)P(X>r+t|X>r)=P(X>t)

P(X>5+5X>5)=P(X>5)P(X>5+5|X>5)=P(X>5)

=e0.0625(5)0.731616=e^{-0.0625(5)}\approx0.731616

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