Question #275736

Determine whether the given function can serve as the probability distribution (probability mass function) of random variable with given range: (a) f(x) = x−2/5 for x = 1, 2, 3, 4, 5 (b) f(x) = 2x/k(k+1) for x = 1, 2, 3, · · · , k


1
Expert's answer
2021-12-06T16:02:04-0500

(a) f(1)=15,  f(2)=0.  f(3)=15.  f(4)=25,  f(5)=35.f(1)=-\frac{1}{5}, \;f(2)=0.\;f(3)=\frac{1}{5}.\;f(4)=\frac{2}{5},\;f(5)=\frac{3}{5}.

All values of a probability mass function must be non-negative.

Thus, the given function cannot serve as the probability distribution.


(b) f(1)=2k(k+1),  f(2)=4k(k+1),  ...,f(k)=2kk(k+1).f(1)=\frac{2}{k(k+1)},\;f(2)=\frac{4}{k(k+1)},\;...,f(k)=\frac{2k}{k(k+1)}.

All values of f are positive.

Σi=1k=2k(k+1)Σi=1ki=2k(k+1)k(k+1)2=1.\Sigma_{i=1}^k=\frac{2}{k(k+1)}\Sigma_{i=1}^ki=\frac{2}{k(k+1)}*\frac{k(k+1)}{2}=1.

Thus, the given function can serve as the probability distribution.


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