Question #275668

10.             A continuous random variable X having values only between 0 and 4 has density function given by f (x) =  1/2 - ax ; where “a”

is constant. Calculate “a”. Find P(1 < X < 2) 


1
Expert's answer
2021-12-07T12:02:38-0500

i.


f(x)dx=04(12ax)dx\displaystyle\int_{-\infin}^{\infin}f(x)dx=\displaystyle\int_{0}^{4}(\dfrac{1}{2}-ax)dx

=[x2ax22]40=28a=1=[\dfrac{x}{2}-\dfrac{ax^2}{2}]\begin{matrix} 4 \\ 0 \end{matrix}=2-8a=1

a=18a=\dfrac{1}{8}

ii.


P(1<X<2)=12(1218x)dxP(1<X<2)=\displaystyle\int_{1}^{2}(\dfrac{1}{2}-\dfrac{1}{8}x)dx

=[x2x216]21=114(12116)=516=[\dfrac{x}{2}-\dfrac{x^2}{16}]\begin{matrix} 2 \\ 1 \end{matrix}=1-\dfrac{1}{4}-(\dfrac{1}{2}-\dfrac{1}{16})=\dfrac{5}{16}


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