Question #275071

A random sample of 40 bys showed a mean weight of 120 lbs with a standard deviation of 12 lbs. The standard weight of their average age is about 130 lbs. Test the hypothesis that the selected boys are significantly lighter that the standard weight at 0.01 level of significance.


1
Expert's answer
2021-12-06T04:58:54-0500

We are given that,

n=40, xˉ=120, s=12,μ=130n=40,\space \bar{x}=120,\space s=12, \mu=130

The hypotheses tested are,

H0:μ=130 vs H1:μ<130H_0:\mu=130\space vs\space H_1:\mu\lt130

We shall apply the student's t distribution to perform this test as follows,

The test statistic is given as,

t=(xˉμ)/(s/n)t^*=(\bar{x}-\mu)/(s/\sqrt{n})

Now,

t=(120130)/(12/40)=10/1.8973666=5.2704628t^*=(120-130)/(12/\sqrt{40})=-10/1.8973666=-5.2704628

The critical value tα,(n1)t_{\alpha, (n-1)} has n1=401=39n-1=40-1=39 degrees of freedom at α=0.01\alpha=0.01 and can be determined using the RR command given below.

> qt(0.01,39)

[1] -2.425841

Therefore, the critical value, t0.01,39=2.425841t_{0.01,39}= -2.425841

tt^* is compared with t0.01,39t_{0.01,39} and the null hypothesis is rejected if t<t0.01,39.t^*\lt t_{0.01,39}.

Since t=5.2704628<t0.01,39=2.425841t^*=-5.2704628\lt t_{0.01,39}= -2.425841, we reject the null hypothesis and conclude that there is sufficient evidence to show that the selected boys are significantly lighter than the standard weight at 1% level of significance.


Need a fast expert's response?

Submit order

and get a quick answer at the best price

for any assignment or question with DETAILED EXPLANATIONS!

Comments

No comments. Be the first!
LATEST TUTORIALS
APPROVED BY CLIENTS