During peak traffic periods, accidents occur in a certain small city at a rate of 4.9 per hour. The morning peak lasts for 1.6 hours. On any given day, the probability that there will be at most 2 accidents during the morning peak period is
The probability that there will be at most 2 accidents during the morning peak period is:
"P(X\\eqslantless2)=P(X=0)+P(X=1)+P(X=2)"
"P(X\\eqslantless2)=\\frac{1.6^{0}*e^{-1.6}}{0!}+\\frac{1.6^{1}*e^{-1.6}}{1!}+\\frac{1.6^{2}*e^{-1.6}}{2!}"
"P(X\\eqslantless2)=0.2019+0.3230+0.2584=0.7834"
There is 78.34% probability of that there will be at most 2 accidents during the morning peak period.
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