The mean grade in a Physics examination was 75 and the standard deviation was 5. Determine the standard scores (z-value) corresponding to a grade of 85
μ=75σ=5x=85Z=x−μσ=85−755=2\mu=75 \\ \sigma = 5 \\ x = 85 \\ Z = \frac{x - \mu}{\sigma} = \frac{85-75}{5} = 2μ=75σ=5x=85Z=σx−μ=585−75=2
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