The mean grade in a Physics examination was 75 and the standard deviation was 5. Determine the standard scores (z-value) corresponding to a grade of 85
"\\mu=75 \\\\\n\\sigma = 5 \\\\\nx = 85 \\\\\nZ = \\frac{x - \\mu}{\\sigma} = \\frac{85-75}{5} = 2"
Comments
Leave a comment