Given a population consists of three numbers (2,5,9).
Consider all possible samples of size 2 which can be drawn from the population.
Find the variance of the sampling distribution of the sample means.
All possible samples:{(2,5), (2,9), (5,9)}.
Sample means for these samples: 3.5, 5.5, 7.
Mean of the sample means: (3.5+5.5+7)/3=5.33
Population mean = (2+5+9)/3=5.33
So, the sample mean is an unbiased estimate of the population mean.
Population variance: "\\sigma^2=\\frac{(2-5.33)^2+(5-5.33)^2+(9-5.33)^2}{3}=8.22"
The variance of the sampling distribution of means: "\\sigma_x^2=\\frac{\\sigma^2(N-n)}{n(N-1)}=\\frac{8.22(3-2)}{2(3-1)}=2.055"
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