The engine made by alpha-x for boats have an average power of 220 horsepower and a standard deviation of 15HP. You can assume the distribution of power follows a normal distribution. Beta-y is testing the engines and will dispute the company's claim if the sample mean is less than 215HP. If they take a sample of 4 engines; what is the probability the mean is less than 215? If beta-y samples 100 engines, what is the probability that the mean will be less than 215?
Solution:
We want to find "P(\\bar X<215)".
Since the population follows a normal distribution, we can conclude that "\\bar X" has a normal distribution with mean 220 HP (μ=220) and a standard deviation of "\\dfrac \u03c3{\\sqrt n}=\\dfrac{15}{\\sqrt4}=7.5" HP.
Now,
"P(\\bar X<215)=P(z<\\dfrac{215-220}{7.5})\n\\\\=P(z<-0.67)\n\\\\\\approx 0.2514"
Next, the sampling distribution of the sample mean is Normal with mean μ=220
and standard deviation "\\dfrac \u03c3{\\sqrt n}=\\dfrac{15}{\\sqrt{100}}=1.5"
Now,
"P(\\bar X<215)=P(z<\\dfrac{215-220}{1.5})\n\\\\=P(z<-3.333..)\n\\\\\\approx 0.00043"
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