Question #261466

The engine made by alpha-x for boats have an average power of 220 horsepower and a standard deviation of 15HP. You can assume the distribution of power follows a normal distribution. Beta-y is testing the engines and will dispute the company's claim if the sample mean is less than 215HP. If they take a sample of 4 engines; what is the probability the mean is less than 215? If beta-y samples 100 engines, what is the probability that the mean will be less than 215?


1
Expert's answer
2021-11-12T11:13:34-0500

Solution:

We want to find P(Xˉ<215)P(\bar X<215).

Since the population follows a normal distribution, we can conclude that Xˉ\bar X  has a normal distribution with mean 220 HP (μ=220) and a standard deviation of σn=154=7.5\dfrac σ{\sqrt n}=\dfrac{15}{\sqrt4}=7.5 HP.

Now,

P(Xˉ<215)=P(z<2152207.5)=P(z<0.67)0.2514P(\bar X<215)=P(z<\dfrac{215-220}{7.5}) \\=P(z<-0.67) \\\approx 0.2514

Next, the sampling distribution of the sample mean is Normal with mean μ=220

 and standard deviation σn=15100=1.5\dfrac σ{\sqrt n}=\dfrac{15}{\sqrt{100}}=1.5

Now,

P(Xˉ<215)=P(z<2152201.5)=P(z<3.333..)0.00043P(\bar X<215)=P(z<\dfrac{215-220}{1.5}) \\=P(z<-3.333..) \\\approx 0.00043

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