The probability that machine P will breakdown is 72
The probability that machine P will not breakdown is 75
The probability that machine Q will breakdown is 113
The probability that machine Q will not breakdown is 118
The probability that at least one machine will be working is PQ′+P′Q+PQ=(72∗118)+(75∗113)+(72∗113)
=7716+(75⋅113)+(72⋅113)=7716+7715+(72⋅113)=7716+7715+776=7737
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