Question #257316
Suppose x is a normally distrubuted random variable with a mean of 30 and standard deviation of 8. Find a value X0 of the random varible of such that. P(x>(Equal too) X)=0.5
1
Expert's answer
2021-10-27T14:04:06-0400
P(XX0)=1P(X<X0)P(X\geq X_0)=1-P(X<X_0)

=1P(Z<X0μσ)=0.5=1-P(Z<\dfrac{X_0-\mu}{\sigma})=0.5

X0μσ=0\dfrac{X_0-\mu}{\sigma}=0

X0=μX_0=\mu

X0=30X_0=30


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