For a Normal distribution with mean, μ
=
2
μ=2
, and standard deviation, σ
=
4
σ=4
,
10% of observations have a value less than Round to 4 decimal places.
10% of observations have a value greater than Round to 4 decimal places.
N(2; 16) = 2 + 4N(0,1)
1). We have to find such value a that P(2 + 4N(0,1) < a) = 0.1
"P(2 + 4N(0,1) < a)=0.1\\to P(N(0,1)<{\\frac {a-2} 4})=0.1\\to {\\frac {a-2} 4} = -1.2816\\to"
"\\to a=-3.1264"
10% of observations have a value less than -3.1264
2). We have to find such value b that P(2 + 4N(0,1) > b) = 0.1
"P(2 + 4N(0,1) >b)=0.1\\to P(N(0,1)>{\\frac {b-2} 4})=0.1\\to {\\frac {b-2} 4} = 1.2816\\to"
"\\to b=7.1264"
10% of observations have a value greater than 7.1264
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