Question #256300

three cards are drawn in succession from a deck without replacement. find the probability distribution for the number of hearts



1
Expert's answer
2021-10-26T13:10:27-0400

There are 13 heart cards in a deck of cards and there are 39 cards which are not heart.

To find the probability distribution of selecting a card of heart.

Let x denotes the number of heart cards in a draw of 3 cards without replacement, so x could take values as 0, 1, 2, and 3.

Probability of selection a heart card =1352= \frac{13}{52}

Probability of selection two heart cards in succession (without replacement) =1352×1251= \frac{13}{52} \times \frac{12}{51}

Probability of selection three heart cards in succession (without replacement) =1352×1251×1150= \frac{13}{52} \times \frac{12}{51} \times \frac{11}{50}

Probability of selection a non-heart card =3952= \frac{39}{52}

Probability of selection two non-heart cards in succession (without replacement) =3952×3851= \frac{39}{52} \times \frac{38}{51}

Probability of selection three non-heart cards in succession (without replacement) =3952×3851×3750= \frac{39}{52} \times \frac{38}{51} \times \frac{37}{50}

Hence P(x=0) =selecting 3 heart cards in succession (without replacement) =3952×3851×3750=0.4135= \frac{39}{52} \times \frac{38}{51} \times \frac{37}{50} = 0.4135

P(x=1) = selecting 1 heart card and 2 non-heart cards in succession (without replacement) =1352×3951×3850=0.1452= \frac{13}{52} \times \frac{39}{51} \times \frac{38}{50} = 0.1452

P(x=2)=selecting 2 heart card and 1 non-heart cards in succession (without replacement) =1352×1251×3950=0.0458= \frac{13}{52} \times \frac{12}{51} \times \frac{39}{50} = 0.0458

P(x=3) = selecting 3 heart cards in succession (without replacement) =1352×1251×1150=0.0129= \frac{13}{52} \times \frac{12}{51} \times \frac{11}{50} = 0.0129

Probability distribution table:


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