Question #254224

the length of 5000 corn cobs produced from a local wholesaler are measured and recorded. the lengths X, are found to be normally distributed with a mean of 9cm and a variance of 0.25cm². Find the probability that a corn cob selected at random from the wholesaler has a length between 8.5cm and 9.25cm.


1
Expert's answer
2021-10-21T12:03:22-0400

XN(μ,σ2)X\sim N(\mu, \sigma^2)

Given μ=9 cm,σ2=0.25 cm2.\mu=9\ cm , \sigma^2=0.25\ cm^2.


P(8.5<X<9.25)=P(X<9.25)P(X8.5)P(8.5<X<9.25)=P(X<9.25)-P(X\leq8.5)

=P(Z<9.2590.5)P(Z8.590.5)=P(Z<\dfrac{9.25-9}{0.5})-P(Z\leq\dfrac{8.5-9}{0.5})

=P(Z<0.5)P(Z1)=P(Z<0.5)-P(Z\leq-1)

0.6914620.1586550.532807\approx0.691462-0.158655\approx0.532807

The probability that a corn cob selected at random from the wholesaler has a length between 8.5cm and 9.25cm is 0.5328.0.5328.



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