Question #254035

Give the following frequency distribution with some missing frequencies

Class

10-20

20-30

30-40

40-50

50-60

60-70

70-80


Frequency

185

f2

34

180

136

f6

50



If the total frequency is 686 and the midian is 42.6 Find out the missing frequencies f2 and f6.


1
Expert's answer
2021-10-21T11:59:40-0400
ClassFrequencyC.F.10201851852030f2185+f2304034219+f24050180399+f25060136535+f26070f6535+f2+f6708050585+f2+f6\def\arraystretch{1.5} \begin{array}{c:c:c} Class & Frequency & C.F. \\ \hline 10-20 & 185 & 185 \\ \hdashline 20-30 & f2 & 185+f2 \\ \hdashline 30-40 & 34 & 219+f2 \\ \hdashline 40-50 & 180& 399+f2 \\ \hdashline 50-60 & 136& 535+f2 \\ \hdashline 60-70 & f6 & 535+f2+f6 \\ \hdashline 70-80 & 50 & 585+f2+f6 \\ \hdashline \end{array}

The total frequency is 686


585+f2+f6=686585+f2+f6=686

f2+f6=101f2+f6=101

median=42.6median=42.6 Then median class is 4050.40-50.

l=40,h=10,f=180,l=40, h=10, f=180, and C=219+f2C=219+f2


median=l+N/2Cf×hmedian=l+\dfrac{N/2-C}{f}\times h

42.6=40+686/2219f2180×1042.6=40+\dfrac{686/2-219-f2}{180}\times 10

124f2=46.8124-f2=46.8

f2=77f2=77

f6=10177=24f6=101-77=24


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