"n_1=10 \\\\\n\nmean = \\bar{x_1} = \\frac{1667+16.29+...+15.88+16.99}{10} = 16.339 \\\\\n\n\\sigma_1 = 0.020 \\\\\n\nn_2 = 10 \\\\\n\n\\bar{x_2} = \\frac{16.19+16.49+...+16.39+16.91}{10}=16.14 \\\\\n\n\\sigma_2 = 0.025"
Now, if two machines are used for filling plastic bottles with a net volume of 16.0 ounces , then the net mean difference between the two machines would be zero
"H_0: \\mu_1 -\\mu_2 = 0 \\\\\n\nH_1: \\mu_1 -\\mu_2 \u2260 0"
It is a two-tailed test
α=0.10
Critical value
"Z_c = 1.645"
Reject H0 if |Z| > 1.645
Test-statistic:
"Z = \\frac{\\bar{x_1} - \\bar{x_2}}{\\sqrt{\\frac{\\sigma^2_1}{n_1} + \\frac{\\sigma_2^2}{n_2}}} \\\\\n\nZ = \\frac{16.339-16.14}{\\sqrt{\\frac{0.02^2}{10} + \\frac{0.025^2}{10}}} \\\\\n\nZ = -19.66"
Here we noticed that "|z| = 19.656 > Z_c = 1.645"
Hence, null hypothesis is rejected
Conclusion: There is enough evidence to claim that the two machines which are used for filling plastic bottles do not have a net volume of 16.0 ounces, at the "\\alpha = 0.1" significance level
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